2y^2-y+1=0

Solution for 2y^2-y+1=0 equation:

Simplifying
2y2 + -1y + 1 = 0

Reorder the terms:
1 + -1y + 2y2 = 0

Solving
1 + -1y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
0.5 + -0.5y + y2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + -0.5y + -0.5 + y2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + -0.5y + y2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + -0.5y + y2 = 0 + -0.5
-0.5y + y2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
-0.5y + y2 = -0.5

The y term is -0.5y.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5y + 0.0625 + y2 = -0.5 + 0.0625

Reorder the terms:
0.0625 + -0.5y + y2 = -0.5 + 0.0625

Combine like terms: -0.5 + 0.0625 = -0.4375
0.0625 + -0.5y + y2 = -0.4375

Factor a perfect square on the left side:
(y + -0.25)(y + -0.25) = -0.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.